t^2-17t+30=0

Solution for t^2-17t+30=0 equation:

t^2-17t+30=0

a = 1; b = -17; c = +30;
Δ = b2-4ac
Δ = -172-4·1·30
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-13}{2*1}=\frac{4}{2}
=2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+13}{2*1}=\frac{30}{2}
=15
$